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Decktrove
Fortified Beachhead
PBRO · The Brothers' War Promos #262p · Rare · released 2022-11-18
Land
As this land enters, you may reveal a Soldier card from your hand. This land enters tapped unless you revealed a Soldier card this way or you control a Soldier.
{T}: Add {W} or {U}.
{5}, {T}: Soldiers you control get +1/+1 until end of turn.
Fortified Beachhead is a rare land from The Brothers' War Promos (2022). It has been printed 5 times across 3 sets, from 2022 to 2023. Recent market prices range from $0.31 to $0.72 depending on printing and finish. It is legal in Pioneer, Modern, Legacy, Vintage, Commander, Oathbreaker, Historic and Brawl.
USD$0.37
USD Foil$0.72
Format legality
Where you can play Fortified Beachhead in sanctioned and popular formats.
StandardNot legal
PioneerLegal
ModernLegal
LegacyLegal
VintageLegal
CommanderLegal
PauperNot legal
OathbreakerLegal
HistoricLegal
BrawlLegal
Penny DreadfulNot legal
All printings (5)
Prices range from $0.31 to $0.72 across finishes. Cheapest printing: The Brothers' War at $0.31.
| Set | No. | Rarity | Price | Foil |
|---|---|---|---|---|
| The Brothers' War Promos | 262s | Rare | — | $0.40 |
| The Brothers' War Promos This page | 262p | Rare | $0.37 | $0.72 |
| The Brothers' War | 370 | Rare | $0.42 | $0.43 |
| The Brothers' War | 262 | Rare | $0.31 | $0.40 |
| Magic Online Promos | 105874 | Rare | — | — |
More from The Brothers' War Promos
Frequently asked questions
Is Fortified Beachhead legal in Commander?
Yes — Fortified Beachhead is legal in Commander (EDH).
What formats is Fortified Beachhead legal in?
Fortified Beachhead is legal in Pioneer, Modern, Legacy, Vintage, Commander, Oathbreaker, Historic and Brawl.
How many times has Fortified Beachhead been printed?
Fortified Beachhead has been printed 5 times across 3 sets, from 2022 to 2023.
What is the cheapest printing of Fortified Beachhead?
The cheapest printing is The Brothers' War (#262) at about $0.31.
Who illustrated Fortified Beachhead?
This printing of Fortified Beachhead was illustrated by Christian Dimitrov.